3.138 \(\int \frac {(a+a \cosh (x))^{3/2}}{x^3} \, dx\)

Optimal. Leaf size=109 \[ \frac {3}{16} a \text {Chi}\left (\frac {x}{2}\right ) \text {sech}\left (\frac {x}{2}\right ) \sqrt {a \cosh (x)+a}+\frac {9}{16} a \text {Chi}\left (\frac {3 x}{2}\right ) \text {sech}\left (\frac {x}{2}\right ) \sqrt {a \cosh (x)+a}-\frac {a \cosh ^2\left (\frac {x}{2}\right ) \sqrt {a \cosh (x)+a}}{x^2}-\frac {3 a \sinh \left (\frac {x}{2}\right ) \cosh \left (\frac {x}{2}\right ) \sqrt {a \cosh (x)+a}}{2 x} \]

[Out]

-a*cosh(1/2*x)^2*(a+a*cosh(x))^(1/2)/x^2+3/16*a*Chi(1/2*x)*sech(1/2*x)*(a+a*cosh(x))^(1/2)+9/16*a*Chi(3/2*x)*s
ech(1/2*x)*(a+a*cosh(x))^(1/2)-3/2*a*cosh(1/2*x)*sinh(1/2*x)*(a+a*cosh(x))^(1/2)/x

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Rubi [A]  time = 0.17, antiderivative size = 109, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {3319, 3314, 3301, 3312} \[ \frac {3}{16} a \text {Chi}\left (\frac {x}{2}\right ) \text {sech}\left (\frac {x}{2}\right ) \sqrt {a \cosh (x)+a}+\frac {9}{16} a \text {Chi}\left (\frac {3 x}{2}\right ) \text {sech}\left (\frac {x}{2}\right ) \sqrt {a \cosh (x)+a}-\frac {a \cosh ^2\left (\frac {x}{2}\right ) \sqrt {a \cosh (x)+a}}{x^2}-\frac {3 a \sinh \left (\frac {x}{2}\right ) \cosh \left (\frac {x}{2}\right ) \sqrt {a \cosh (x)+a}}{2 x} \]

Antiderivative was successfully verified.

[In]

Int[(a + a*Cosh[x])^(3/2)/x^3,x]

[Out]

-((a*Cosh[x/2]^2*Sqrt[a + a*Cosh[x]])/x^2) + (3*a*Sqrt[a + a*Cosh[x]]*CoshIntegral[x/2]*Sech[x/2])/16 + (9*a*S
qrt[a + a*Cosh[x]]*CoshIntegral[(3*x)/2]*Sech[x/2])/16 - (3*a*Cosh[x/2]*Sqrt[a + a*Cosh[x]]*Sinh[x/2])/(2*x)

Rule 3301

Int[sin[(e_.) + (Complex[0, fz_])*(f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[CoshIntegral[(c*f*fz)/d
+ f*fz*x]/d, x] /; FreeQ[{c, d, e, f, fz}, x] && EqQ[d*(e - Pi/2) - c*f*fz*I, 0]

Rule 3312

Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sin
[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f, m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1])
)

Rule 3314

Int[((c_.) + (d_.)*(x_))^(m_)*((b_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[((c + d*x)^(m + 1)*(b*Si
n[e + f*x])^n)/(d*(m + 1)), x] + (Dist[(b^2*f^2*n*(n - 1))/(d^2*(m + 1)*(m + 2)), Int[(c + d*x)^(m + 2)*(b*Sin
[e + f*x])^(n - 2), x], x] - Dist[(f^2*n^2)/(d^2*(m + 1)*(m + 2)), Int[(c + d*x)^(m + 2)*(b*Sin[e + f*x])^n, x
], x] - Simp[(b*f*n*(c + d*x)^(m + 2)*Cos[e + f*x]*(b*Sin[e + f*x])^(n - 1))/(d^2*(m + 1)*(m + 2)), x]) /; Fre
eQ[{b, c, d, e, f}, x] && GtQ[n, 1] && LtQ[m, -2]

Rule 3319

Int[((c_.) + (d_.)*(x_))^(m_.)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Dist[((2*a)^IntPart[n
]*(a + b*Sin[e + f*x])^FracPart[n])/Sin[e/2 + (a*Pi)/(4*b) + (f*x)/2]^(2*FracPart[n]), Int[(c + d*x)^m*Sin[e/2
+ (a*Pi)/(4*b) + (f*x)/2]^(2*n), x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && EqQ[a^2 - b^2, 0] && IntegerQ[n
+ 1/2] && (GtQ[n, 0] || IGtQ[m, 0])

Rubi steps

\begin {align*} \int \frac {(a+a \cosh (x))^{3/2}}{x^3} \, dx &=\left (2 a \sqrt {a+a \cosh (x)} \text {sech}\left (\frac {x}{2}\right )\right ) \int \frac {\cosh ^3\left (\frac {x}{2}\right )}{x^3} \, dx\\ &=-\frac {a \cosh ^2\left (\frac {x}{2}\right ) \sqrt {a+a \cosh (x)}}{x^2}-\frac {3 a \cosh \left (\frac {x}{2}\right ) \sqrt {a+a \cosh (x)} \sinh \left (\frac {x}{2}\right )}{2 x}-\frac {1}{2} \left (3 a \sqrt {a+a \cosh (x)} \text {sech}\left (\frac {x}{2}\right )\right ) \int \frac {\cosh \left (\frac {x}{2}\right )}{x} \, dx+\frac {1}{4} \left (9 a \sqrt {a+a \cosh (x)} \text {sech}\left (\frac {x}{2}\right )\right ) \int \frac {\cosh ^3\left (\frac {x}{2}\right )}{x} \, dx\\ &=-\frac {a \cosh ^2\left (\frac {x}{2}\right ) \sqrt {a+a \cosh (x)}}{x^2}-\frac {3}{2} a \sqrt {a+a \cosh (x)} \text {Chi}\left (\frac {x}{2}\right ) \text {sech}\left (\frac {x}{2}\right )-\frac {3 a \cosh \left (\frac {x}{2}\right ) \sqrt {a+a \cosh (x)} \sinh \left (\frac {x}{2}\right )}{2 x}+\frac {1}{4} \left (9 a \sqrt {a+a \cosh (x)} \text {sech}\left (\frac {x}{2}\right )\right ) \int \left (\frac {3 \cosh \left (\frac {x}{2}\right )}{4 x}+\frac {\cosh \left (\frac {3 x}{2}\right )}{4 x}\right ) \, dx\\ &=-\frac {a \cosh ^2\left (\frac {x}{2}\right ) \sqrt {a+a \cosh (x)}}{x^2}-\frac {3}{2} a \sqrt {a+a \cosh (x)} \text {Chi}\left (\frac {x}{2}\right ) \text {sech}\left (\frac {x}{2}\right )-\frac {3 a \cosh \left (\frac {x}{2}\right ) \sqrt {a+a \cosh (x)} \sinh \left (\frac {x}{2}\right )}{2 x}+\frac {1}{16} \left (9 a \sqrt {a+a \cosh (x)} \text {sech}\left (\frac {x}{2}\right )\right ) \int \frac {\cosh \left (\frac {3 x}{2}\right )}{x} \, dx+\frac {1}{16} \left (27 a \sqrt {a+a \cosh (x)} \text {sech}\left (\frac {x}{2}\right )\right ) \int \frac {\cosh \left (\frac {x}{2}\right )}{x} \, dx\\ &=-\frac {a \cosh ^2\left (\frac {x}{2}\right ) \sqrt {a+a \cosh (x)}}{x^2}+\frac {3}{16} a \sqrt {a+a \cosh (x)} \text {Chi}\left (\frac {x}{2}\right ) \text {sech}\left (\frac {x}{2}\right )+\frac {9}{16} a \sqrt {a+a \cosh (x)} \text {Chi}\left (\frac {3 x}{2}\right ) \text {sech}\left (\frac {x}{2}\right )-\frac {3 a \cosh \left (\frac {x}{2}\right ) \sqrt {a+a \cosh (x)} \sinh \left (\frac {x}{2}\right )}{2 x}\\ \end {align*}

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Mathematica [A]  time = 0.06, size = 69, normalized size = 0.63 \[ \frac {(a (\cosh (x)+1))^{3/2} \left (3 x^2 \text {Chi}\left (\frac {x}{2}\right ) \text {sech}^3\left (\frac {x}{2}\right )+9 x^2 \text {Chi}\left (\frac {3 x}{2}\right ) \text {sech}^3\left (\frac {x}{2}\right )-8 \left (3 x \tanh \left (\frac {x}{2}\right )+2\right )\right )}{32 x^2} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + a*Cosh[x])^(3/2)/x^3,x]

[Out]

((a*(1 + Cosh[x]))^(3/2)*(3*x^2*CoshIntegral[x/2]*Sech[x/2]^3 + 9*x^2*CoshIntegral[(3*x)/2]*Sech[x/2]^3 - 8*(2
+ 3*x*Tanh[x/2])))/(32*x^2)

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fricas [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+a*cosh(x))^(3/2)/x^3,x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (ha
s polynomial part)

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giac [B]  time = 0.15, size = 170, normalized size = 1.56 \[ \frac {1}{32} \, \sqrt {2} {\left (\frac {9 \, a^{\frac {3}{2}} x^{2} {\rm Ei}\left (\frac {3}{2} \, x\right ) + 3 \, a^{\frac {3}{2}} x^{2} {\rm Ei}\left (\frac {1}{2} \, x\right ) + a^{\frac {3}{2}} x^{2} {\rm Ei}\left (-\frac {1}{2} \, x\right ) - 6 \, a^{\frac {3}{2}} x e^{\left (\frac {3}{2} \, x\right )} - 6 \, a^{\frac {3}{2}} x e^{\left (\frac {1}{2} \, x\right )} + 2 \, a^{\frac {3}{2}} x e^{\left (-\frac {1}{2} \, x\right )} - 4 \, a^{\frac {3}{2}} e^{\left (\frac {3}{2} \, x\right )} - 12 \, a^{\frac {3}{2}} e^{\left (\frac {1}{2} \, x\right )} - 4 \, a^{\frac {3}{2}} e^{\left (-\frac {1}{2} \, x\right )}}{x^{2}} + \frac {2 \, a^{\frac {3}{2}} x^{2} {\rm Ei}\left (-\frac {1}{2} \, x\right ) + 9 \, a^{\frac {3}{2}} x^{2} {\rm Ei}\left (-\frac {3}{2} \, x\right ) + 4 \, a^{\frac {3}{2}} x e^{\left (-\frac {1}{2} \, x\right )} + 6 \, a^{\frac {3}{2}} x e^{\left (-\frac {3}{2} \, x\right )} - 8 \, a^{\frac {3}{2}} e^{\left (-\frac {1}{2} \, x\right )} - 4 \, a^{\frac {3}{2}} e^{\left (-\frac {3}{2} \, x\right )}}{x^{2}}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+a*cosh(x))^(3/2)/x^3,x, algorithm="giac")

[Out]

1/32*sqrt(2)*((9*a^(3/2)*x^2*Ei(3/2*x) + 3*a^(3/2)*x^2*Ei(1/2*x) + a^(3/2)*x^2*Ei(-1/2*x) - 6*a^(3/2)*x*e^(3/2
*x) - 6*a^(3/2)*x*e^(1/2*x) + 2*a^(3/2)*x*e^(-1/2*x) - 4*a^(3/2)*e^(3/2*x) - 12*a^(3/2)*e^(1/2*x) - 4*a^(3/2)*
e^(-1/2*x))/x^2 + (2*a^(3/2)*x^2*Ei(-1/2*x) + 9*a^(3/2)*x^2*Ei(-3/2*x) + 4*a^(3/2)*x*e^(-1/2*x) + 6*a^(3/2)*x*
e^(-3/2*x) - 8*a^(3/2)*e^(-1/2*x) - 4*a^(3/2)*e^(-3/2*x))/x^2)

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maple [F]  time = 0.08, size = 0, normalized size = 0.00 \[ \int \frac {\left (a +a \cosh \relax (x )\right )^{\frac {3}{2}}}{x^{3}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+a*cosh(x))^(3/2)/x^3,x)

[Out]

int((a+a*cosh(x))^(3/2)/x^3,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (a \cosh \relax (x) + a\right )}^{\frac {3}{2}}}{x^{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+a*cosh(x))^(3/2)/x^3,x, algorithm="maxima")

[Out]

integrate((a*cosh(x) + a)^(3/2)/x^3, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (a+a\,\mathrm {cosh}\relax (x)\right )}^{3/2}}{x^3} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + a*cosh(x))^(3/2)/x^3,x)

[Out]

int((a + a*cosh(x))^(3/2)/x^3, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a \left (\cosh {\relax (x )} + 1\right )\right )^{\frac {3}{2}}}{x^{3}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+a*cosh(x))**(3/2)/x**3,x)

[Out]

Integral((a*(cosh(x) + 1))**(3/2)/x**3, x)

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